zhengzhou , china
[email protected]Feb 07, 2017 So 1.54 Cum of dry materials (cement, sand and aggregate) is required to produce 1 Cum of concrete. Volume of Cement required = 1/(1+2+4) X 1.54 = 1/7 X 1.54 = 0.22 Cum. Volume of Sand required = 2/7 X 1.54 = 0.44 Cum or 15.53 cft. Volume of Aggregate required = 4/7 X 1.54 = 0.88 Cum or 31.05 cft. Note: 1 cubic meter = 35.29 cubic feet
Leave Us NowYou can also send a message to us by this email [email protected], we will reply to you within 24 hours.Now tell us your need,there will be more favorable prices!
Nov 05, 2019 Top chaliye main apko Cement, Sand, Aggregate aur Water ki Quantity ko nikalna batata hu.. Sab se pehle hum, M25 Grade Concrete ka jo Ratio hain uska summation nikal ke rakh lete hain. Sum of Ratio of Cement , Sand and Aggregate = 1+1+2 = 4. Ab hame Concrete ke WET Volume ko Dry Volume me convert karna hoga.
Reinforced cement concrete or RCC calculator can be used to calculate M15, M20 and M25 mix ratio of cement, sand and jelly. At materialtree.Contact Us Ambuja Cement.com, you can also shop for superior quality cement bags at best market price.
4 rows Strength of RCC is defined as compressive strength after 28 days, expressed as M15, M20, where M ...
M20 grade concrete materials will be calculated for 10.39 cu.m volume. For M20 nominal mix, the proportion of cement, sand and aggregate is 1:1.5:3 (cement : sand : aggregate). So, sum of proportion = 5.5. So, the quantity of cement for RCC slab in 10.39 cu.m will be calculated as follow :-Quantity of cement = ratio of cement/total ratio x total volume = 1/5.5 x 10.39 = 1.88 cu.m
Dec 16, 2019 calculate quantity of cement sand and aggregate for 10 cubic metre concrete and take M20 grade of concrete. Solve;- given :-Wet volume of conc = 10 m3. Mix ratio in m20 = 1 :1.5 :3. Total proportion = 1 + 1.5 + 3 = 5.5. Density of cement = 1440 kg/m3. 1 bag cement = 50 kg. 1 cubic meter = 35.32 cubic feet Solution:-Dry volume = wet volume 1.54
Apr 01, 2015 Assuming bulk densities of materials per cubic meter, cubic feet and cubic yards as follows: Cement = 1500 kg/m3 = 93.642 lb/ft3 = 2528.332 lb/cubic yards Sand = 1700 kg/m3 = 105 lb/ft3 = 2865.443 lb/cubic yards Coarse aggregates = 1650 kg/m3 = 103 lb/ft3 = 2781.166 lb/cubic yards Specific gravities of concrete materials are as follows: Cement = 3.15 Sand = 2.6 Coarse aggregates …
Aug 03, 2018 CALCULATION FOR SAND QUANTITY; Consider volume of concrete = 1m 3 . Dry Volume of Concrete = 1 x 1.54 = 1.54 m 3 Sand= (1.5/5.5) x 1.54 = 0.42 m 3 ∴ 1.5 is a part of Sand, 5.5 is sum of ratio . Density of Sand is 1450/m 3. For KG = 0.42 x 1450 = 609 kg As we know that 1m 3 = 35.31 CFT